Three years ago, the average age of a family of 5 members was 17 years

1.	Three years ago, the average age of a family of 5 members was 17 years. A baby having been born and the average age of the family is the same as three years ago. The present age of the baby (in years) is:1. 22. 1.53. 2.44. 3
Answer» Correct Answer - Option 1 : 2 Given: 3 years ago average age of 5 members is 17 years. Formula used: Average = Sum of values/number of values Calculation: 3 years ago average age of 5 members is 17 years Sum of ages of 5 members, 3 years ago ⇒ 17 × 5 = 85 Average of Present age of 5 members = 20 years Sum of present ages of 5 members = 20 × 5 = 100 But a baby born and average remains same i.e 17 years Sum of present ages of 6 members = 17 × 6 = 102 Age of baby = 102 - 100 = 2 years ∴ The age of baby is 2 years.

Three years ago, the average age of a family of 5 members was 17 years. A baby having been born and the average age of the family is the same as three years ago. The present age of the baby (in years) is:1. 22. 1.53. 2.44. 3

Answer» Correct Answer - Option 1 : 2

Given:

3 years ago average age of 5 members is 17 years.

Formula used:

Average = Sum of values/number of values

Calculation:

3 years ago average age of 5 members is 17 years

Sum of ages of 5 members, 3 years ago

⇒ 17 × 5 = 85

Average of Present age of 5 members = 20 years

Sum of present ages of 5 members = 20 × 5 = 100

But a baby born and average remains same i.e 17 years

Sum of present ages of 6 members = 17 × 6 = 102

Age of baby = 102 - 100 = 2 years

∴ The age of baby is 2 years.

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