1.

Threemoles of theidealgas areexpandedisothermallyfrom avolumeof 300 cm^(3) to2.5L at300 Kagainsta pressureof1.9 atm. Calculatethe workdonein L andand joules.

Answer»


Solution :Numberof molesof a gas= n=3 mol
Initialvolume`=V_(1) = 300 cm^(3)= 0.3 L(or dm^(3))`
Finalvolume`= V_(2) = 2.5 L`
Externalpressure `= P_(EX)= 1.9atm `
Temperature= T = 300 K
Since theexpansiontakesplaceagainstconstantpressureit isirreversible PROCESS and workis givenby
`W=- P_("ex") (V_(2)-V_(1))`
=- 1.9 (2.5 -0.3)
`=- 4.18 L atm `
Now , 1 L atm= 101 . 3 J
`:. W= - 4.18 xx101 .3 =- 423 .4 J`


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