Throram 7.2

1.	Throram 7.2
Answer» Proof :in ∆ BAD and ∆CAD ,BA = CA ( given)angle BAD = angle CAD ( By. Construction) AD =AD (common) ∆BAD =(~) ∆ CAD (By SAS Congruence) angle DBA=angle DCA. ( By C.P.C.T ) angle B = angle C. ( Hence proved ) ∆ ABCD AD Midian of BC Given: triangle ABC is an isosceles in which AB =AC To prove : angle B =angle CConstruction:Draw the bisector of angle A . Let D be the point of intersection of this bisector angle A on angle BC . Statement: angles opposite to equal side of an isosceles triangle are equal

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