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Tick the correct answer and justify: In `DeltaA B C`.AB = `6sqrt(3)`cm. AC = 12 cm and BC = 6 cm. The angle B is: (A) 120 (B) 60 (C) 90 (D) 45 |
Answer» `cosB=((AB)^2+(BC)^2-(AC)^2)/(2(AB)(BC))` `cosB=(108+36-144)/(2*(6sqrt3)*6)=0` Hence, `/_B=pi/2` |
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