Saved Bookmarks
| 1. |
Time is measured using a stop watch of least count 0.1 second In 10 oscilation time taken is 20.0 second Find maximum permissible error in time period . |
|
Answer» `T = ("Total time")/("Total oscillation") = (t)/(10)` `rArr DeltaT = (Deltat)/(10) = (0.1)/(10)` `DeltaT = 0.01` second . |
|