1.

Time period of a simple pendulum is 2s. If its length is increased by 4 times, then its period becomes……….

Answer»

`16s`
`12s`
`8s`
`4s`

SOLUTION :`T propto sqrt(L)`
`(T_1)/(T_2)= sqrt((l_1)/(l_2))`
`(2)/(T_2)= sqrt((l)/(4L)) IMPLIES T_(2)= 4s`.


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