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Time period of mars to revolve around Sun is 8 times greater than that of Mercury. If distance of Mercury from Sun is 5.79xx10^10 m then that of Mars is approximately …... . |
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Answer» TIME PERIOD `T PROPR^(3/2)` `:.T_"Mars"/T_"Mercury"=(r_"Mars"/r_"Mercury")^(3/2)` `:.(8)^(2/3)=r_"Mars"/r_"Mercury"` `:.4=r_"Mars"/(5.79xx10^10)` `:.r_"Mars"=4xx5.79xx10^10` `=23.16xx10^10m` |
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