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Time required to decompose SO_(2)Cl_(2) to half of the initial amount is 60 minutes .If the decomposition is a first order reaction ,calculate the rate constant of the reaction,=. |
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Answer» Solution :60 minute =`60xx60` SEC. But this time is `t_((1)/(2))` for half of the initial amount `therefore t_((1)/(2)=60xx60` sec For a FIRST order reaction `K=(0.693)/(60xx60s)` `=1.925xx10^(-4) s^(-1)` |
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