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Time taken by a body in `(20 +-0.2)` second in undergoing a displacement of `(200 +-5)`m. Calculate the percentage error in calculation of velcoity. |
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Answer» Correct Answer - `+- 3.5%` `upsilon =(s)/(t) = (200)/(20) =10m//s` `(Deltaupsilon)/(upsilon)xx100 = +-((Deltas)/(s) +(Detlat)/(t))xx100` `=+-((5)/(200) +(0.2)/(20))xx100` `=+- (2.5+1) =+-3.5%` |
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