Time taken for an electron to complete one revolution in the Bohr orbi

1.	Time taken for an electron to complete one revolution in the Bohr orbit of hydrogen atom is
Answer» `(4pi^(2) mr^(2))/(nh)` `(nh)/(4pi^(2)mr)` `(2pimr)/(N^(2) h^(2))` `(h)/(2pi mr)` Solution :By Bohr POSTULATE, `mv r = n (h)/(2pi) or v = (nh)/(2pi mr)` No. of revolution per sec `= ("Velocity")/("Circumference of the orbit")` `= (v)/(2pi r) = (nh)/(2pi mr) xx (1)/(2pi r) = (nh)/(4pi^(2) mr^(2))` `:.` TIME taken for one revolution `= (4pi^(2) mr^(2))/(nh)`

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