Titration of l_(2) produced from 0.1045 g of primary standard KlO_(3) required 30.72 mL of sodium thiosulphate as shown below : lO_(3)^(-) + 5l^(-) + 6H^(+) to 3l_(2) + 3H_(2) Ol_(2) + 2S_(2)O_(3)^(2-) to 2l^(-) + S_(4)O_(6)^(2-) The molarity of sodium thiosulphate ion is :

Titration of l_(2) produced from 0.1045 g of primary standard KlO_(3)

1.	Titration of l_(2) produced from 0.1045 g of primary standard KlO_(3) required 30.72 mL of sodium thiosulphate as shown below : lO_(3)^(-) + 5l^(-) + 6H^(+) to 3l_(2) + 3H_(2) Ol_(2) + 2S_(2)O_(3)^(2-) to 2l^(-) + S_(4)O_(6)^(2-) The molarity of sodium thiosulphate ion is :
Answer» `0.079` `0.095` `0.084` `0.064` SOLUTION :`{:(lO_(3)^(-) + 5l^(-) + 6H^(+) to 3l_(2) + 3H_(2) O ),(ul(3l_(2) + 6S_(2)O_(3)^(2-) to 6l^(-) + 3S_(4)O_(6)^(2-))),(lO_(3)^(-) + 6S_(2)O_(3)^(2-) + 6H^(+) to L^(-) + 3S_(4)O_(6)^(2-)):}` Mole of `KlO_(3) -= 6 " moles of " S_(2)O_(3)^(2-)` Mole of `KlO_(3)= (0.1045)/(21.4) = 4.88 xx 10^(-4)` Mole `S_(2)O_(3)^(2-) " used " = 4.88 xx 10^(-4) xx 6` ` = 2.93 xx 10^(-3)` ` (M xx 30.72)/1000= 2.93 xx 10^(-3)` ` :. M = 0.095`