To 50 mL of 0.5 M H_(2)SO_4 75 mL of 0.25 M H_2SO_4 is added. What is the concentration of the final solution if its volume is 125 mL?

To 50 mL of 0.5 M H_(2)SO_4 75 mL of 0.25 M H_2SO_4 is added. What is

1.	To 50 mL of 0.5 M H_(2)SO_4 75 mL of 0.25 M H_2SO_4 is added. What is the concentration of the final solution if its volume is 125 mL?
Answer» Solution :No. of MOLES in 0.05 litre of `H_(2)SO_(4) = M XX V` (litre) `=0.5 xx 0.05 = 0.0025` No. of moles in 0.0075 litre of `H_(2)SO_(4)` added `=0.25 xx 0.075` `=0.01875` TOTAL no. of moles in 0.125 litre of `H_(2)SO_(4) = 0.025 + 0.01875` =0.04375 `therefore` MOLARITY of `H_(2)SO_(4) = (0.04375)/(0.0125)= 0.35 M`