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To 500cm^(3) of water, 3.0 xx 10^(-3) kg acetic acid is added. If 23% of acetic acid is dissociated, what will be the depression in freezing point? K_(f) and density of water are 1.86 K kg mol^(-1) and 0.997 g cm^(-3) respectively. |
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Answer» Solution :`{:(,CH_(3)COOHhArrCH_(3)COO^(-)+H^(+),),("Initial","1 mole00 ",),("After disso. ","1 - 0.230.230.23","Total = 1.23 moles"):}` `THEREFORE " van't Hoff factor, i = 1.23"` Mass of water (SOLVENT) `=500xx0.997=498.5g` No. of moles of ACETIC acid `=(3xx10^(-3)xx10^(3))/(60)=0.05` `therefore"Molality of the solution "=(0.05)/(498.5)xx1000=0.1` `DeltaT_(f)=iK_(f)m=1.23xx1.86xx0.1=0.228K` |
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