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To a man walking at the rate of 3 km/h the rain appears to fall vertically. When he increases his speed to 6km/h it appears to meet him at an angle of 450 with vertical. Find the angle made by the velocity of rain with the vertical and its value. |
Answer» Solution : From the diagram `TAN45^(0) = (3)/(y)………(1)` and `TANTHETA =(3)/(y)……………(2)` From (1) and (2) `theta=45^(@)` and `:. Sin45^(@)=(3)/(V_(R)),(1)/(sqrt(2))=(3)/(V_(R)) ""V_(R)=3sqrt(2) kmph` |
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