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To a man walking at the rate of 3km/h the tain appears to fall vertically. When he increases his speed to 6km/h it appears to meet him at an angle of 45^(@) with vertical. Find the angle made by the velocity of rain with the vertical and its value. |
Answer» Solution : From the diagram `TAN 45^(@) = (3)/(y)` ….(i) and `Tan theta = (3)/(y)` ……..(2) From (1) and (2) `theta = 45^(@)` and `therefore sin 45^(@) = (3)/(V_(R)), (1)/(sqrt(2)) = (3)/(V_(R))` `V_(R) = 3sqrt(2)` kmph |
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