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To Complete A Piece Of Work A Takes Twice The Time Of B And Thrice The Time Of C. If All Working Together Can Finish The Same Work In 8 Days, Then How Many Days Are Required To Finish The Work By B Alone? |
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Answer» SUPPOSE, A takes X days to finish a piece of work, so B will take X/2 days, and C will take X/3 days Then, (1/X+2/X+3/X) = 1/8 6/x= 1/8 X= 48 days So B alone can finish the work in 48/2= 24 days. Suppose, A takes X days to finish a piece of work, so B will take X/2 days, and C will take X/3 days Then, (1/X+2/X+3/X) = 1/8 Solving the above equation: 6/x= 1/8 X= 48 days So B alone can finish the work in 48/2= 24 days. |
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