To dissolve 0.9 g metal, 100 mL of 1 N HCl is used. What is the equivalent weight of metal? A 7B 9C 10D 6

To dissolve 0.9 g metal, 100 mL of 1 N HCl is used. What is the equiva

1.	To dissolve 0.9 g metal, 100 mL of 1 N HCl is used. What is the equivalent weight of metal? A 7B 9C 10D 6
Answer» 0.9gms metal REQUIRES 100ml of 1N HCl⇒ Volume of HCl=100mlNormality of HCl=1N⇒ Weight of HCl= 1000N.Eq.Wt×V [∵ Normality formula] = 10001×1×100 =0.1gmWe KNOW, Equivalent Weight of Metal is the mass of metal required to produce 1GM of H 2 ⟶(1)Also, We know 0.1gm of HCl gives 0.1gm H 2 ⇒ 1gm HCl Gives 1gm H 2 Now, if 0.9gm metal requires 0.1gm HCl⇒1gm HCl will require 0.11×0.9 gm metal∴ Mass of metal which produces 1gm H 2 =9gm∴ From (1) Equivalent Weight of Metal= 9gm