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To estimate `g` (from `g = 4 pi^(2)(L)/(T^(2))`), error in measurement of `L` is `+- 2%` and error in measurement of `Tis +- 3%` The error in estimated `g` will beA. `+-8%`B. `+-6%`C. `+-3%`D. `+-5%` |
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Answer» `g = 4pi^(2) (l)/(T^(2))` `(Deltal)/(l) =2% = +- 2 xx 10^(-2)` `(DeltaT)/(T) = +- 3% = +- 3 xx 10^(-2) rArr (Deltag)/(g) = (Deltal)/(l) + (2DeltaT)/(T) = 2 xx 10^(-2) + 2 xx 3 xx 10^(-2) = 8 xx 10^(-2) = +- 8%` . |
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