1.

To find molelular mass of diabasic acid by silver salt method following graph is plotted then approximate molecular weight of acid is - where y = weight of silver residue ( in gm) x = weight of silver salt (in gm)

Answer»

160 gm
158 gm
320 gm
240 gm

Solution :`TAN 30^(@) = (W_(Ag))/(W_(Ag - "Salt")) = (1)/(sqrt3)`
`(W_("salt"))/(W_(Ag)) = sqrt3`
`M_(WT) "of" H_(2)X = 2 (108 (W_("Salt"))/(W_(Ag )) - 107)`
`= 2 (108 XX sqrt3 - 107)`
`= 2 (187.056 - 107)`
`= 2 xx 80.056`
`= 160.112 gm`


Discussion

No Comment Found

Related InterviewSolutions