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To find the point of contact P-=(x_(1), y_(1)) of a tangent to the graph of y=f(x) passing through origin O, we equate the slope of tangent to y=f(x) at P to the slope of OP. Hence we solve the equation f'(x_(1))=(f(x_(1)))/(x_(1)) to get x_(1) and y_(1). The equation |ln mx|=px where m is a positive constant has a single root for |
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Answer» <P>`0 LT p lt m//e` |
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