1.

To find the point of contact P-=(x_(1), y_(1)) of a tangent to the graph of y=f(x) passing through origin O, we equate the slope of tangent to y=f(x) at P to the slope of OP. Hence we solve the equation f'(x_(1))=(f(x_(1)))/(x_(1)) to get x_(1) and y_(1). The equation |ln mx|=px where m is a positive constant has a single root for

Answer»

<P>`0 LT p lt m//e`
`p lt e//m`
`0 lt p lt e//m`
`p GT m//e`

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