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To get a maximum current through a resistance of `2.5Omega` one can use m rows of cells each row having n cells . The internal resistance of each cell is `0.5Omega`. What are the values of m and n, if the total number of cells are 20?A. `m=2, n=10`B. m=4, n=5C. m=5, n=4D. n=2, m=10

Answer» Correct Answer - A
Total number of cells `(m+n)=20`
For maximum current, R = nr/m ….(i)
`rArr " " 2.5=n xx0.5//m` or n = 5 m
From Eq. (i), `m xx 5m = 20` , or `m^(2)=4`
`rArr m = 2`, therefore `n = 5xx2=10`


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