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To get maximum current through a resistance of `2.5Omega,` one can use m rows of cells, each row having n cells. The internal resistance of each cell is `0.5 Omega` what are the values of n and m, if the total number of cells is 45.A. 3, 15B. 5, 9C. 9,5D. 15,3 |
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Answer» Correct Answer - D d. For maximum current, net resistance of cells must be equal to `2.5 Omega` i.e., `(n(0.5))/m = 25`………….(i) and `m xx n = 45` …………..(ii) Solving we get n = 15, m= 3 . |
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