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To increase the length of an electric string of radius 3.5 mm by 1/20 the of its initial length, within its elastic limit, a 10N force is required, Calculate the Young's modulus for the material of the string. |
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Answer» SOLUTION :We KNOW that , `Y=(FL)/(pir^2l)` Here, `F=10N,l=1/20Land r=3.5mm=0.0035m.` `thereforeY=(10timesL)/(3.14times(0.0035)^2times1/20)=5.2 TIMES 10^6 N.m^-2` |
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