1.

To measure gravitational acceleration by using simple pendulum, length of pendulum (0.8pm0.01) m and periodic time (2.5pm0.12) s. Find percentage error in measurement of g.

Answer»

10.85
12.75
15.85
21.12

Solution :`T=2pisqrt((l)/(g))`
`:.T^(2)=(4pi^(2)l)/(g)`
`:.g=(4pi^(2)l)/(T^(2))`
`[:.4pi^(2)` = constant]
`:.` % ERROR in measurement of g,
`(DELTAG)/(g)xx100%=(Deltal)/(l)xx100%+2(DeltaT)/(T)xx100%`
`=(0.01)/(0.8)xx100%+2XX(0.12xx100)/(2.5)`
`=1.25%+9.6%`
`=10.85%`


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