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To measure gravitational acceleration by using simple pendulum, length of pendulum (0.8pm0.01) m and periodic time (2.5pm0.12) s. Find percentage error in measurement of g. |
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Answer» 10.85 `:.T^(2)=(4pi^(2)l)/(g)` `:.g=(4pi^(2)l)/(T^(2))` `[:.4pi^(2)` = constant] `:.` % ERROR in measurement of g, `(DELTAG)/(g)xx100%=(Deltal)/(l)xx100%+2(DeltaT)/(T)xx100%` `=(0.01)/(0.8)xx100%+2XX(0.12xx100)/(2.5)` `=1.25%+9.6%` `=10.85%` |
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