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To measure the quantity of MnCl_(2) dissolved in an aqueous solution, it was completely converted to KMnO_(4) using the reaction, MnCl_(2)+K_(2)S_(2)O_(8)+H_(2)Orarr KMnO_(4)+underset("(equation not balanced)")(H_(2)SO_(4)+HCl) Few drops of concetrated HCl were added to this solution and gently warmed. Further, oxalix acid (225 g) was added in portions till the colour of the permanganate on disappeared. The quantity of MnCl_(2) (in mg) present in the intial solution is _____ (Atomic weights in "g mol"^(-1):Mn=55, Cl=35.5) |
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Answer» `C_(2)O_(4)^(-)+MnO_(4)^(-)OVERSET(H^(+))rarrCO_(2)` `m_(eq)" of "C_(2)O_(4)^(-)=m_(eq)" of "MnO_(4)^(-)` `2xx0.225//90=axx5` `a=1xx[55+71]` `=126mg` |
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