1.

To neutralize completely 20 mL of 0.1M aqueous solution of phosphorus acid (H_(3)PO_(3)) the volume of 0.1M aqueous KOH solution required is

Answer»

40 mL
20 mL
10 mL
60 mL

Solution :Since `H_(3)PO_(3)` is dibasic, 0.1 M solution =- 0.2 N solution.
`underset(("Acid"))(N_(1)V_(1))=underset(("Base"))(N_(2)V_(2))`
`(0.2 N)xx20 mL)=(0.1N)xxV_(2)`
`V_(2)=((0.2N)xx(20ML))/((0.1N))=40 mL.`


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