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    				| 1. | To observe an elevation of boiling point of 0.05 ""^(@)C , the amount of solute (Mol. Wt = 100) to be added to 100 g of water (K_b = 0.5) is | 
| Answer» Solution :`DeltaT_(b) = 0.05 ""^(@)C, K_(b) =0.5, W_(A) =100g` `M_(B) = 100 , W_(B) = ?` `therefore DELTA T_(b) = K_(b) xx (W_B)/(M_B) xx (1000)/(W_A) . rArr 0.05 =0.5 xx (W_B)/(100) xx (1000)/(100)` `rArr 5 xx 10^(-2) = 5 xx 10^(-1) xx (W_B)/(10) rArr W_(B) = 1 g` | |