1.

To obtain of water at 50^(@)C, how many grams of stea at its stea point must be passed to 70 g of ice at 0^(@)C.

Answer»

SOLUTION :
HEAT PRODUCED by steam=Heat ABSORBED by ICE.
`M[590]=5600+3500`
`M=(9100)/(590)=910//59g=15.42g`


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