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| 1. |
To obtain of water at 50^(@)C, how many grams of stea at its stea point must be passed to 70 g of ice at 0^(@)C. |
Answer» SOLUTION : HEAT PRODUCED by steam=Heat ABSORBED by ICE. `M[590]=5600+3500` `M=(9100)/(590)=910//59g=15.42g` |
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