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To study the decomposition of hydrogen iodide, a student fills an evacuated 3 litre flask with 0.3 mol of HI gas and allows the reaction to proceed at 500^(@)C. At eauilibrium he found the concentration of HI which is equal to 0.05 M. Calculate K_(C) and K_(P) for this reaction. |
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Answer» Solution :`V=3L` `[HI]_("initial")=(0.3" mol")/(3L)=0.1M` `[HI]_(EQ)=0.05M` `2HI(g)hArrH_(2)(g)+I_(2)(g)` `K_(C)=([H_(2)][I_(2)])/([HI]^(2))` `=(0.025xx0.025)/(0.05xx0.05)` `K_(C)=0.25` `K_(P)=K_(C)(RT)^(Deltang)` `Deltan_(g)=2-2=0` `K_(P)=0.25(RT)^(0)=0.25` |
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