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To test the quality of a tennis ball, you drop it onto the floor from a height of 4.00 m. It rebounds to a height of 2.00 m. If the ball is in contact with the floor for 12.0 ms, what is its average acceleration during that contact? Take `g= 98 m//s^2.` |
Answer» Correct Answer - A::B::C::D `a_(av)=(Deltav)/(Deltat)=(v_f-v_i)/(Deltat)` `=(sqrt(2gh_f)+sqrt(2gh_i))/(Deltat)` `=(sqrt(2xx9.8xx2)+sqrt(2xx9.8xx4))/(12xx10^-3)` `=1.26xx10^3 m//s^2` |
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