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To what volume should an HCl soln (w/w% 75%) should be diluted such that its concentration becomes 0.1 M, if initial volume of soln is 500ml. |
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Answer» Let say density of solution is g/ml. ∵ 100 g of solution contain = 75g HCl ∴ 500g of solution contain = \(\frac{75 \times 500}{100} = 75 \times 5g\; HCl\) ∴ Number of moles of HCl = \(\frac{75\times 5}{36.5} = 10.27\, mol\) ∴ Initial concentration of HCl solution = \(\frac{10.27}{500}\times 1000= 20.55 M\) Let say, After dilution the volume of solution become V then, \(V \times 0.1 = 20.55 \times 500\) \(V = \frac{20.55\times 500}{0.1}\) \(= 102750 \,ml\) \(V = 102.75 \,l\) |
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