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To which orbit the electron in the hydrogen atom will jump after absorbing 1.94 xx 10^(-18)J of energy ? |
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Answer» Solution :Energy of electron in the nth orbit of H-atom is GIVEN by: `E_(n) = - (21.8 xx 10^(-19))/(n^(2)) J:. E_(1) = - 21.8 xx 10^(-19) J` (`:' n = 1` for ground STATE of H-atoms) After absorbing `1.94 xx 10^(-8) J` of energy, the energy of the electron will be `= -21.8 xx 10^(-19) + 1.94 xx 10^(-18) J = - 2.4 xx 10^(-19) J` Thus, `- (21.8 xx 10^(-19))/(n^(2)) = - 2.4 xx 10^(-19) or n^(2) = (21.8)/(2.4) = 9 or n = 3` Thus, the electron will jump to the third orbit. |
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