1.

To which orbit the electron in the hydrogen atom will jump after absorbing 1.94 xx 10^(-18)J of energy ?

Answer»

Solution :Energy of electron in the nth orbit of H-atom is GIVEN by:
`E_(n) = - (21.8 xx 10^(-19))/(n^(2)) J:. E_(1) = - 21.8 xx 10^(-19) J` (`:' n = 1` for ground STATE of H-atoms)
After absorbing `1.94 xx 10^(-8) J` of energy, the energy of the electron will be
`= -21.8 xx 10^(-19) + 1.94 xx 10^(-18) J = - 2.4 xx 10^(-19) J`
Thus, `- (21.8 xx 10^(-19))/(n^(2)) = - 2.4 xx 10^(-19) or n^(2) = (21.8)/(2.4) = 9 or n = 3`
Thus, the electron will jump to the third orbit.


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