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To which orbit the electron in the hydrogen atom will jump on absorbing `12.1 eV` of energy? |
Answer» Energy of electron in the nth orbit of H-atom is `E_(n) = (-13.6)/(n^(2)) eV :. E_(1) = -13.6 eV` After absorbing 12.1 eV, the energy will be `= -13.6 + 12.1 eV = -1.5 eV` Thus, `(-13.6)/(n^(2)) = - 1.5 eV or n^(2) = 9 or n = 3` Thus, electron will jump to 3rd orbit. |
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