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Tollen's reagent is used for the detection fo aldehyde when a solution of AgNO_(3) is added to glucose with NH_(4)OH then gloconic acid is formed Ag^(+)toe^(-)toAg,E_(Red)^(@)=0.8V C_(6)H_(12)O_(6)+H_(2)Oto"gluconic acid"(C_(6)H_(12)O_(7)) +2H^(+)+2e^(-),E_(red)^(@)=-0.05V Ag(NH_(3))_(2)^(+)+e^(-)toAg(s)+2NH_(3),E_(red)^(@)=0.337V ["Use "2.303xx(RT)/(F)=0.0592 and (F)/(RT)=38.92" at "298K] Q. 2Ag^(+)+C_(6)H_(12)O_(6)+H_(2)Oto2Ag(s)+C_(6)H_(12)O_(7)+2H^(+) Find In K of this reaction |
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Answer» 66.13 (i) `AG^(+)+e^(-)TOAG(s),E_(red)^(o)=0.8V` (ii) `C_(6)H_(12)O_(6)+H_(2)OtoC_(6)H_(12)O_(7)+2H^(+)+2e^(-),E_("oxid")=-0.05V` ltBrgt Hence, for reaction `2Ag^(+)+C_(6)H_(12)O_(6)+H_(2)Oto2Ag_((s))+C_(6)H_(12)O_(7)+2H^(+)` `E_(cell)^(o)=(0.8-0.05)` `=0.75V` `E_(cell)^(o)=E_("ANODE")^(o)-E_("cathode")^(o)` `=[-0.05-(-0.8)]V` on the basis of oxidised electrode potential `=0.75V` By nernst EQUATION `E_(cell)=E_(cell)^(o)=(2.303RT)/(nF)log_(10)K` At equilibrium `E_(cell)=0` `thereforeE_(Cell)^(o)=(2.303RT)/(2)log_(10)K` `0.75=(0.0592)/(2)log_(10)K) ` `log_(10)K=(2xx0.75)/(0.0592)=25.33` or In `K=2.303xxlog_(10)K` `=2.303xx25.33=58.35`. |
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