1.

Total charge required for the oxidation of two moles Mn_3O_4 intoMnO_4^(2-)in presence of alķaline medium is 2.0 xx 10^(x), x is

Answer»


Solution :`Mn_3O_4 overset(OH^(-))to MnO_4^(-2)`
` +(8)/(3) ""+6`
charge in oxidation state =` 6 -(8)/(3)`
For 3 Mn atoms `=3[6-(8)/(3)] = 10`
For 1 mole = 10
For 2 MOLES =` 2 XX 10 = 20 = 2 xx 10^(1) , x =1`


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