Total no. of electrons present in 48 g of Mg are(1) 24 N2 N(3) 20 N(4)

1.	Total no. of electrons present in 48 g of Mg are(1) 24 N2 N(3) 20 N(4) respeatom(1)(3)
Answer» 24 gm of Magnesium contains=N atoms. Where N=6.023 x 10^24 48 gm of Magnesium 48 gm of Mg contains=2 N atoms. 1 Atom of Mg contains=12 electrons Mg 2+ ion will contain=12–2=10 electrons 2N Mg-ions will contain = 10 x 2N electrons =10 x 2 x 6.022 x 10^23 =1.2044 x 10^25 electrons

Total no. of electrons present in 48 g of Mg are(1) 24 N2 N(3) 20 N(4) respeatom(1)(3)

Answer»

24 gm of Magnesium contains=N atoms. Where N=6.023 x 10^24

48 gm of Magnesium 48 gm of Mg contains=2 N atoms.

1 Atom of Mg contains=12 electrons

Mg 2+ ion will contain=12–2=10 electrons

2N Mg-ions will contain

= 10 x 2N electrons

=10 x 2 x 6.022 x 10^23

=1.2044 x 10^25 electrons