Total no. of voids in `0.5` mole of a compound forming hexagonal closed packed structure are :A. `6.022xx10^23`B. `3.011xx10^23`C. `9.033xx10^23`D. `4.516xx10^23`

Total no. of voids in `0.5` mole of a compound forming hexagonal close

1.	Total no. of voids in `0.5` mole of a compound forming hexagonal closed packed structure are :A. `6.022xx10^23`B. `3.011xx10^23`C. `9.033xx10^23`D. `4.516xx10^23`
Answer» Correct Answer - C In hexagonal close packed structure , there are 6 atoms per unit cell total number of voids = 6+12=18 `therefore` total number of voids per atom = `18/6=3` `therefore` In 1 mole compound the total number of voids `=3xx6.022xx10^23` `therefore` In 0.5 mole compound , the total number of voids `=3xx0.5xx6.023xx10^23` `=9.034xx10^23`

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Total no. of voids in `0.5` mole of a compound forming hexagonal closed packed structure are :A. `6.022xx10^23`B. `3.011xx10^23`C. `9.033xx10^23`D. `4.516xx10^23`

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