1.

Total number of atoms in 44 g CO_(2) is

Answer»

`6*02xx10^(23)`
`6*02xx10^(24)`
`1*806xx10^(22)`
`18*06xx10^(22)`.

Solution :TOTAL no. of MOLES of `CO_(2)` in 44 g `= (44)/(44) = 1`
1 mole `CO_(2)` = 1 mole C + 2 mole O atoms
= 3 mole atom
`= 3xx6*02xx10^(23) = 1*806xx10^(24)`


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