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Total number of atoms in 44 g `CO_(2)` isA. `6*02xx10^(23)`B. `6*02xx10^(24)`C. `1*806xx10^(22)`D. `18*06xx10^(22)`. |
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Answer» Correct Answer - C Total no. of moles of `CO_(2)` in 44 g `= (44)/(44) = 1` 1 mole `CO_(2)` = 1 mole C + 2 mole O atoms = 3 mole atom `= 3xx6*02xx10^(23) = 1*806xx10^(24)` |
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