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Total number of atoms present in 34 g of `NH_3` isA. `4xx10^23`B. `4.8xx10^21`C. `2xx10^23`D. `48xx10^23` |
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Answer» No. of moles of 34g of `NH_3=34/17=2` No. of molecules `=2xx6.023xx10^23` No. of atoms in one molecules of `NH_3`=4 No. of atoms in `2xx6.023xx10^23 " molecules of NH_3` `=4xx2xx6.023xx10^23=48.18xx10^23` |
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