Total number of electrons present in 1.7 g of ammonia is

1.	Total number of electrons present in 1.7 g of ammonia is
Answer» `6.022xx10^(23)` `(6.022xx10^(22))/1.7` `(6.022xx10^(24))/1.7` `(6.022xx10^(23))/1.7` Solution :No. of electrons present in ONE ammonia (`NH_(3)`) molecule (7 + 3) = 10 No. of moles of ammonia =`("MASS")/("Molar Mass")` `=(1.7g)/(17gmol^(-1))` 0.1 mol No. of molecules present in 0.1 mol of ammonis `=0.1xx6.022xx10^(23)=6.022xx10^(22)` No. of electrons present in 0.1 mol of ammonialtbrtgt`10xx6.022xx10^(22)-6.022xx10^(23)`

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