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Total number of moles of `EDTA^(4-)` required to produce octahedral complex with `Mg^(2+)` is |
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Answer» Correct Answer - 1 `Mg^(2+)+ underset(("Hexadentate ligand"))(EDTA^(4-))to underset(("Octahedral complex"))([Mg(EDTA)]^(2-)) CN=6` |
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