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Total pressure observed after opening the stopcock is [neglecting the volume of the tube connecting the two bulbs] |
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Answer» 1.33 ATM `(0.1 xx 2)/(RT) + (0.2 xx 1)/(RT) = (P xx 0.1)/(RT) + (P xx 0.2)/(RT)` `implies P = (0.4)/(0.3) = 1.33 atm.` |
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