Total time taken by a laser beam to return to the earth after reflecti – InterviewSolution

InterviewSolution

1.	Total time taken by a laser beam to return to the earth after reflection from the moon is 2.56 s. Calculate the distance of moon from the earth. Take velocity of light in vacuum `=3xx10^8m//s.`
Answer» Correct Answer - `3.84xx10^km` Here, `t = 2.56s, r = ? C=3xx10^8m//s` AS `r = cxx(t)/(2)` `:. r= 3xx10^8xx(2.56)/(2) = 3.84xx10^8m` `=3.84 xx10^5 km.

Discussion

No Comment Found

Related InterviewSolutions

What is a systematic error ? How can it be removed ?
The dimensional formula for angular momentum isA. `[ML^(0)L^(2)T^(-2)]`B. `[ML^(2)T^(-1)]`C. `[MLT^(-1)]`D. `[ML^(2)T^(-2)]`
if the universe were shrunk to the size, of earth, how large would the earth be on this scale?
The dimensional formula for conductance isA. `[M^(-1) L^(-2) T^3 A^(-2)]`B. `[M^1 L^2 T^(-3) A^2]`C. `[M^(-1)L^(-2) T^(-3) A^2]`D. `[M^(-1)L^(-2)T^3 A^2]`
The estimated size of observable universe is of the order of………
Give two examples of non dimensional veriables.
What are the dimensions of rate of flow?
Age of the universe is about `10^(10)` years whereas the mankind has existed for `10^6` years. How many seconds would the man have existed if age of universe were one day.
State the number of significant figures in the following : (a) `0.007m^2` (b) `2.64 xx10^(24) kg` (c) `0.2370 g cm^(-3)` (d) `6.320 J` (e ) `6.032 N m^(-2)` (f) `0.0006032 m^2`
A student measures the time period of `100` ocillations of a simple pendulum four times. The data set is `90 s`, 91 s, 95 s, and 92 s`. If the minimum division in the measuring clock is `1 s`, then the reported men time should be:A. `(92 +-2)s`B. `(92 +- 5)s`C. `(92 +- 1.8)s`D. `(92 +- 3)s`