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Total volume of atoms present in a face centred cubic unit cell of a metal is ........ (r is atomic radius)(A) \(\cfrac{8}{3}\pi r^3\) (B) \(8\pi r^3\)(C) \(\cfrac{16}{3}\pi r^3\)(D)\(\cfrac{4}{3}\pi r^3\) |
Answer» Correct answer is: (C)\(\cfrac{16}{3}\pi r^3\) Volume occupied by one atom of radius ‘r’=\(\cfrac{4}{3}\pi r^3.\) \(\therefore\)In fcc unit cell, there are 4 atoms present. present in fcc unit cell = \(4\times\cfrac{4}{3}\pi r^3=\cfrac{16}{3}\pi r^3\) |
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