Trace the path of a ray of light passing through a glass prism (ABC) a

1.	Trace the path of a ray of light passing through a glass prism (ABC) as shown in the figure. If the refractive index of glass is √3, find out the value of the angle of emergence from the prism.
Answer» Answer: 60° Explanation: $\frac{sin i}{sin r} = \frac{N(air)}{N(glass)} \\=> \frac{sin 30}{ 2 sin (e)} = \frac{1}{\sqrt{3} } \\=> \frac{\sqrt{3} }{2} = sin (e) \\=> e = 60$ we GOT 30° by APPLYING SNELL's law e= ANGLE of EMERGENCE

Trace the path of a ray of light passing through a glass prism (ABC) as shown in the figure. If the refractive index of glass is √3, find out the value of the angle of emergence from the prism.

Answer»

Answer:

60°

Explanation:

$\frac{sin i}{sin r} = \frac{N(air)}{N(glass)} \\=> \frac{sin 30}{ 2 sin (e)} = \frac{1}{\sqrt{3} } \\=> \frac{\sqrt{3} }{2} = sin (e) \\=> e = 60$

we GOT 30° by APPLYING SNELL's law