Trajectory of particle in projectile motion is y=(x-x^(2)//80), x and y are in metre. Projectile range is on horizontal plane.

Trajectory of particle in projectile motion is y=(x-x^(2)//80), x and

1.	Trajectory of particle in projectile motion is y=(x-x^(2)//80), x and y are in metre. Projectile range is on horizontal plane.
Answer» SOLUTION :`y=X tan theta-(GX^(2))/(2u^(2)cos^(2)theta)` `y=(x-(x^(2))/(80)), theta=45^(@)` `U^(2)=800` `u=sqrt(800)` `u_(y)=u_(y)-gt` `u_(y)=20-10` `u_(y)=10 , v_(x)=20` `tan theta=(1)/(2) rArr theta=tan^(-1)((1)/(2))`