InterviewSolution
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InterviewSolution
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Treatment of ammonia with excess of ethyl chloride will yieldA. Diethyl amineB. ethaneC. Tetraethyl ammonium chlorideD. methyl amine |
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Answer» Correct Answer - C `C_(2)H_(5)Cioverset(NH_(3))rarr C_(2)H_(5)-NH_(2)` `overset(C_(2)H_(5)CI)rarr(C_(2)H_(5))_(2)-NH` `overset(C_(2)H_(5)CI)rarr(C_(2)H_(5))_(3)N` `overset(C_(2)H_(5)CI)rarr [underset("Tetraethylammonium chloride")[C_(2)H_(5)-underset(C_(2)H_(5))underset(|)overset(C_(2)H_(5))overset(|)N-C_(2)H_(5)]CIbar]` If `NH_(3)` is in excess then `1^(@)` amine will be the main product if `C_(2)H_(5)CI` is in excess then mixture of `1^(@)` ,`2^(@)` ,`3^(@)` and quaternary amine is obtained . |
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