Truth table for system of four `NAND` gates as shown in figure is : .A. `{:(A,B,Y),(0,0,0),(0,1,1),(1,0,1),(1,1,0):}`B. `{:(A,B,Y),(0,0,0),(0,1,0),(1,0,1),(1,1,1):}`C. `{:(A,B,Y),(0,0,1),(0,1,1),(1,0,0),(1,1,0):}`D. `{:(A,B,Y),(0,0,1),(0,1,0),(1,0,0),(1,1,1):}`

Truth table for system of four `NAND` gates as shown in figure is : .A

1.	Truth table for system of four `NAND` gates as shown in figure is : .A. `{:(A,B,Y),(0,0,0),(0,1,1),(1,0,1),(1,1,0):}`B. `{:(A,B,Y),(0,0,0),(0,1,0),(1,0,1),(1,1,1):}`C. `{:(A,B,Y),(0,0,1),(0,1,1),(1,0,0),(1,1,0):}`D. `{:(A,B,Y),(0,0,1),(0,1,0),(1,0,0),(1,1,1):}`
Answer» Correct Answer - A `Y=overline(overline((A. overline(A.B))).(overline(overline(A.B).B)))= (overline(overline(A. overline(A.B))))+(overline(overline(overline(A.B)B)))` `Y=A.(overline(A)+ overline(B))+(overline(A)+overline(B)).B` `=A.overline(A)+A. overline(B)+ overline(A).B+ B. overline(B)` `Y=(A.overline(B))+(overline(A).B)`.

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Truth table for system of four `NAND` gates as shown in figure is : .A. `{:(A,B,Y),(0,0,0),(0,1,1),(1,0,1),(1,1,0):}`B. `{:(A,B,Y),(0,0,0),(0,1,0),(1,0,1),(1,1,1):}`C. `{:(A,B,Y),(0,0,1),(0,1,1),(1,0,0),(1,1,0):}`D. `{:(A,B,Y),(0,0,1),(0,1,0),(1,0,0),(1,1,1):}`

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