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Tumbull's andprussiant'sbluerespectively are KFe^(II)[Fe^(III)(CN)_(6)] andKFe^(II)(Fe^(11)(CN)_(6)]

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Solution :TURNBULL's bluecolour is oatained where `Fe^(2+)` salt REACTS with `K_(3)[(Fe^(III)CN)_(6)]` and prassion'sbluecolour is obtained when `Fe^(2+)` saltswith `K_(4)[(Fe^(II)CN)_(6)]`
`Fe^(II)CI_(2) + K_(3)[Fe^(III)Fe(CN_(6))] underset("turnball's blue")(KFe^(III)(CN)_(6)] + 2KCI`
`Fe^(III)CI_(3) + K_(4)[Fe^(II)(CN_(6))] rarr underset("prassion's blue")(KFe^(III)Fe(CN)_(6)] + 3KCI`
Hence true.


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